0=3(v^2+10v-3000)

Solution for 0=3(v^2+10v-3000) equation:

0=3(v^2+10v-3000)

We move all terms to the left:

0-(3(v^2+10v-3000))=0

We add all the numbers together, and all the variables

-(3(v^2+10v-3000))=0


We calculate terms in parentheses: -(3(v^2+10v-3000)), so:

3(v^2+10v-3000)

We multiply parentheses

3v^2+30v-9000

Back to the equation:

-(3v^2+30v-9000)


We get rid of parentheses

-3v^2-30v+9000=0

a = -3; b = -30; c = +9000;
Δ = b2-4ac
Δ = -302-4·(-3)·9000
Δ = 108900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{108900}=330$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-330}{2*-3}=\frac{-300}{-6}
=+50
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+330}{2*-3}=\frac{360}{-6}
=-60
$